Pyramid Thirteen, deal #20
HardChecked as winnableAbout this deal
This is one of the harder deals of Pyramid Thirteen: only 0% of the quick simulated games won it, and the solver had to search for a while before finding the way.
The bottom row starts with Ace of Spades, 10 of Clubs, 4 of Diamonds, 6 of Diamonds, 10 of Diamonds, 4 of Clubs and King of Spades, and the 6 of Spades sits at the very top.
None of the bottom cards add up to 13 with each other, so the first help has to come from the stock.
2 Kings lie in the pyramid; each one leaves on its own as soon as nothing rests on it.
14 times a card lies across one of its own partners, so those two cards can never leave together and need other partners.
The most crowded value is 5 with 4 cards in the layout, while only 1 of its partners (8) are in the layout too; the rest come from the stock.
The solver's winning line has 66 moves.
Deal facts
- Difficulty
- Hard
- Solver's winning line
- 66 moves, 44 of them stock turns
- Quick simulated games won
- 1 of 200 (0%)
- Card at the top
- 6 of Spades
- Cards in the layout
- 28
- Cards in the stock
- 24
- Pairs ready at the start
- 0
- Locked pairs
- 14
How to approach it
- Start by naming a partner for each locked card. If both partners of a locked card are also in the pyramid, free them first; otherwise wait for one from the stock.
- Because nothing pairs at the start, turn the stock slowly and look at what each new waste card could free before you use it.
- This is a hard deal: use undo to test an idea, and the hint button if you are completely stuck.
A winning start
These are the first moves of the solver's winning line. Open them only if you want a nudge.
Show the first three moves
- Clear the King of Spades on its own.
- Turn a card from the stock.
- Pair the 10 of Clubs with the 3 of Hearts.
All 30 deals of Pyramid Thirteen · Rules of Pyramid Thirteen